Object-Oriented Programming

CPSC 260 Operator Overloading and Convert Constructors Slide 25 Implicit conversion The compiler decides to use a conversion constructor void myFunc( Complex param ) { } double value = 5.5; myFunc( value ); The convert constructor is called implicitly to convert value to a Complex when it is passed as a parameter to myFunc CPSC 260 Operator Overloading and

CPSC | 260 | Object-Oriented Programming | lecture notes | CPSC 260 Operator Overloading 

CPSC 260 Lifetime, Scope and Memory Organization Page 7 int k ; static int i ; static void q ( void ); void p ( int a ) { static int b = 50; int c ; int* w = new int; c = a + a ; b += c ; if ( a != 1 ) q (); } static void q ( void ) { k = 1; p( k ); } int main () { int j ; int k = 2; p ( k ); } CPSC 260 Lifetime, Scope and Memory Organization Page 8 int k ; static int i ; static void q ( void ); void p ( int a ) { st

CPSC | 260 | Object-Oriented Programming | lecture notes | CPSC 260 Lifetime  Scope and M

CPSC_260_-_Midterm_1_-_2006_T2_-_Questions.pdf-MARKING KEY The University of British

CPSC 260 Linked Lists Slide 1 Linked Lists Using dynamic memory allocation we can specify the capacity of an IntVector at run-time It is expensive to increase the capacity of the IntVector : • allocate memory to a larger array • copy the data from the original array to the new array • release the memory allocated to the original array It is not possible to increas

CPSC | 260 | Object-Oriented Programming | lecture notes | CPSC 260 Linked Lists Slide 1 

Name: MARKING KEY Student No: MARKING KEY CPSC 260 Final Examination Monday, April 23, 2007 Page 19 of 20 Continue your answers here – make sure to identify the questions whose answers are here! Name: MARKING KEY Student No: MARKING KEY CPSC 260 Final Examination Monday, April 23, 2007 Page 20 of 20 Continue your answers here – make sure to identify the questio

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