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101Fa15Exam1VersionA.pdf
101Fa15Exam1VersionA.pdf
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101Fa15Exam1VersionA.pdf-Physics 101 Hour Exam 1 O...
101Fa15Exam1VersionA.pdf-Physics 101 Hour Exam 1 October
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101Fa15Exam1VersionA.pdf-Physics 101 Hour Exam 1 October
Page 10
21)
22)
The next two questions pertain to the situation described below
.
A block of mass m
1
= 5 kg on a frictionless inclined plane of angle 30
o
is connected by a cord over a
small frictionless pulley to a second block of mass m
2
= 3.3 kg hanging vertically. We find that the
tension in the string is T = 29.3 N.
What is the acceleration of mass m
1
?
a.
32.37 m/s
2
b.
9.81 m/s
2
c.
0.95 m/s
2
d.
2.01 m/s
2
e.
0 m/s
2
The cord now breaks. The acceleration of m
1
a.
stays in the same direction
b.
Goes to zero
c.
reverses direction
Page 8 of 9
Page 11
23)
24)
Mass (M) can be measured in kilograms (kg) and velocity (v) can be measured in meters per
second (m/s). Kinetic energy is given by E = ½ Mv
2
. Which of the following is a unit of kinetic
energy?
a.
kg m
2
/s
2
b.
m s
2
/kg
c.
kg s /m
Which of the following is necessarily NOT in equilibrium?
a.
A parachuter descending at constant velocity
b.
A car accelerating along a road
c.
A pendulum at rest
d.
A train moving along a straight track at constant speed
e.
A crate resting on the floor
Page 9 of 9
Page 12
5/1/2015
1
Physics 101 Formulas
Kinematics
v
ave
= Δ
x
/Δt
a
ave
= Δ
v
/Δt
v = v
0
+ at
x = x
0
+ v
0
t +
1
/
2
at
2
v
2
= v
0
2
+ 2aΔx
g = 9.8 m/s
2
= 32.2 ft/s
2
(near Earth’s surface)
Dynamics
Σ
F
= m
a
F
g
= Gm
1
m
2
/ R
2
F
g
= mg (near Earth’s surface)
f
s,max
= μ
s
F
N
Gravitational constant, G = 6.7 x 10
–11
N∙m
2
/kg
2
f
k
= μ
k
F
N
a
c
= v
2
/ R = ω
2
R
Work & Energy
W
F
= FDcos(θ)
K =
1
/
2
mv
2
= p
2
/2m
W
NET
= ΔK = K
f
– K
i
E = K + U
W
nc
=ΔE = E
f
– E
i
= (K
f
+ U
f
) – (K
i
+ U
i
)
U
grav
= mgy
Impulse & Momentum
Impulse
I
=
F
ave
Δt = Δ
p
F
ave
Δt = Δ
p
= m
v
f
– m
v
i
F
ave
= Δ
p
/Δt
Σ
F
ext
Δt = Δ
P
total
=
P
total,final
– P
total,initial
(momentum conserved if Σ
F
ext
= 0)
x
cm
= (m
1
x
1
+ m
2
x
2
)/(m
1
+ m
2
)
Rotational Kinematics
ω = ω
0
+ αt
θ= θ
0
+ ω
0
t +
1
/
2
αt
2
ω
2
= ω
0
2
+ 2αΔθ
Δx
T
= RΔθ v
T
= Rω
a
T
= Rα
(rolling without slipping: Δx = RΔθ
v = Rω
a = Rα)
1 revolution = 2π radians
Rotational Statics & Dynamics
τ= Fr sin θ
Στ = 0 and ΣF=0 (static equilibrium)
Στ = Iα
W = τθ (work done by a torque)
L
= I
ω
Σ
τ
ext
Δt = Δ
L
(angular momentum conserved if Δ
τ
ext
= 0)
K
rot
=
1
/
2
Iω
2
= L
2
/2I
K
total
= K
trans
+ K
rot
=
1
/
2
mv
2
+
1
/
2
Iω
2
Fluids
P = F/A
,
P(d) = P(0) + ρgd change in pressure with depth d
ρ = M/V (density)
Buoyant force F
B
= ρgV
dis
= weight of displaced fluid
Flow rate Q = v
1
A
1
= v
2
A
2
continuity equation
(area of circle A = πr
2
)
P
1
+
1
/
2
ρv
1
2
+ ρgy
1
= P
2
+
1
/
2
ρv
2
2
+ ρgy
2
Bernoulli equation
ρ
water
= 1000 kg/m
3
1m
3
= 1000 liters
1 atm = 1.01 x 10
5
Pa
1 Pa = 1 N/m
2
Moments of Inertia (I)
I = Σmr
2
(for a collection of point
particles)
I =
1
/
2
MR
2
(solid disk or cylinder)
I =
2
/
5
MR
2
(solid ball)
I =
2
/
3
MR
2
(hollow sphere)
I = MR
2
(hoop or hollow cylinder)
I =
1
/
12
ML
2
(uniform rod about center)
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