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Booth School of Business
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Problem 4: Antibodies (a) P(D=0) = 1 – P(D=1) = 1 – 0.01 = 0.99 (Answer) P(T=1|D=0) = 0.01 (Answer) P(T=1 |D=1) = 0.97 (Answer) (b) (c) Joint distribution table D 0 1 T 0 0.9801 0.0273 1 0.0099 0.0097 (d) Using Bayes’ theorem P(D=1 | T=1) = # $ =1 %