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Survey of Chemistry II

1 MODULE 5 UNIT 2 Assignment Part A 1. Ammonia is produced in great quantity by bringing about a reaction between nitrogen and hydrogen, as seen in the following equation: (6 marks) N 2 + 3H 2  2NH 3 Use this equation to calculate the number of moles of ammonia produced when: a) 10 moles of nitrogen react with excess gaseous hydrogen. Number of moles of NH 3 = 3 moles of H 2 x 10 moles of N 2 1 moles of N 2 = 20 moles b) 30 moles of hydrogen react with excess nitrogen. Number of moles of N 2 = 2 moles of NH 3 x 30 moles of H 2 3 moles of H 2 = 20 moles c) 20 moles of hydrogen react with 40 moles of nitrogen. Hint: One of the reactants will be in excess, that is, it will not be consumed completely. Number of moles of NH 3 = 1 moles of N 2 x 40 moles of N 2 1 mole of H 2 = 13.3 moles 2 2. When iron reacts with oxygen at high temperatures, a magnetic iron oxide is produced: 3Fe + 2O 2  Fe 3 O 4 a. How many moles of iron and oxygen are required to produce 10 moles of magnetic iron oxide? (4 marks) Number of moles of Fe = 2 moles of O2 x 10 moles of Fe3O4 1 mole of Fe3O4 = 20 moles of Fe Number of moles of O2 = 3 moles of Fe x 10 moles of Fe3O4 1 mole of Fe3O4 = 30 moles of O2 3 b. How many moles of oxygen are required to react with 30 moles of iron? (2 marks) Number of moles of O2 = 30 moles of Fe x 2 moles of O2 3 mole of Fe = 20 moles of O2 c. If a reaction is brought about between 60 moles of iron and 60 moles of oxygen, i) which reactant will be in excess and by how many moles? Number of moles of Fe = 60 moles of Fe x 1 moles of Fe3O4 3 mole of Fe = 20 moles of Fe3O4 Number of moles of O2 = 60 moles of O2 x 1 moles of Fe3O4 2 mole of O2 = 30 moles of O2 Check: 30 moles of Fe3O4 x 2 moles of O2 x 1 molesof Fe3O4 1 molesof Fe3O4 = 30 x 2 / 1 = 60 moles Therefore oxygen is in excess by 20 moles ii) calculate the number of moles of magnetic iron oxide produced. Hint : To find which reactant is in excess, calculate how many moles of one reactant are required to react with the other reactant. (4 marks) Number of moles of Fe2O4 = 20 moles of Fe3O4 x 3 moles of Fe 1 mole of Fe3O4 = 60 moles of Fe The number of moles of Fe3O4 is 60 moles Total 16 points Submission Instructions 4 Submit your assignment using the drop box on the Assignment page for this unit. https://olmoodle.ontariolearn.com/mod/resource/view.php?id=348999

CHEM | 1152 | Survey of Chemistry II | homework | 1 MODULE 5 UNIT 2 Assignment P

MODULE 2 UNIT 2 Assignment Part A 1. What’s the total number of orbitals in the valence shell of an atom? How many electrons can each orbital contain? 2 marks There are a total number of 4 orbitals in the valence shell of an atom, and each orbital can hold 2 electrons. 2. Indicate how many full and half-full orbitals there are in the valence shell of the following elements: (2 marks each) a) Krypton 4 full orbitals & no half-full orbitals b) Germanium 4 half-full orbitals & no full orbitals c) Tellurium 2 full orbitals and 2 half-full orbitals d) Gallium 3 half full orbitals & no full orbitals e) Potassium 1 full orbital & 3 half-full orbitals 10 marks 3. Explain, in word, how to represent, using Lewis structures, the electronic configuration of the following elements: a) Silicon has 4 valence electrons so there will be 4 dots around the Si symbol. b) Phosphorus has 5 valence electrons so there will be 5 dots around the P symbol. c) Fluorine has 7 valence electrons, so there will be 7 dots around the F symbol. d) Argon has 8 valence electrons so there will be 8 dots around the Ar symbol. 4 marks Total 16 marks Submission Instructions Submit your assignment using the drop box on the Assignment page for this unit. https://olmoodle.ontariolearn.com/mod/resource/view.php?id=348947

CHEM | 1152 | Survey of Chemistry II | homework | MODULE 2 UNIT 2 Assignment Par

Biology 1108 Exam 1 1. Myoglobin CORRECT If the O2-binding curves were plotted for the following molecules, which curve would be to the left of all the others? 2. diaphragm contracts (moves down), increase volume of chest cavity decrease pressure in chest cavity air rushes inward, requires ATP energy CORRECT Inhalation 3. more O2 than CORRECT In acidic tissues, hemoglobin releases it does in less acidic environments. 4. organic (Substance made plants or animals) compound required by an organism as a vital nutrient in limited amounts CORRECT vitamin 5. releasing bound O2 at lower PO2 conditions than hemoglobin does. CORRECT Myoglobin beneﬁts muscle cells by 6. the immobilization of cilia lining the airways. CORRECT One eﬀect of cigarette smoking on the lungs is 7. the heart relaxes, the atria and ventricle valves open, pulmonary and aortic valves are shut, 4 chambers are ﬁling with blood CORRECT what happen in the heart during diastole 8. Nasal cavity-pharynx-larynx-trachea-bronchi-bronchioles- alveoli CORRECT Pathway of air into the lungs during inhalation 9. found in invertebrates with many cell layers CORRECT open circulatory system 10. both have ability to bind with oxygen CORRECT Myoglobin & hemoglobin

BIO | 1108 | Principles of Biology II | exam | Biology 1108 Exam 1 1. Myoglob

Study Activity - Chapter 27 - The Reproductive System Male Reproductive Anatomy 1. Trace the path taken by a sperm from the site of its formation to the site of fertilization. Epididymis  ductus/vas deferens  ejaculatory duct  urethra 2. List the male accessory glands and their secretions and functions. Seminal vesicles : Produces viscous alkaline seminal fluid – Fructose, citric acid, coagulang enzyme (vesiculase), prostaglandins – Enhance sperm molity or ferlizing ability (70% of volume of semen) – Duct of seminal vesicle joins ductus deferens to form ejaculatory duct Prostate •Encircles urethra inferior to bladder •Secretes milky, slightly acid ﬂuid – Citrate (nutrient source) – Enzymes – Prostate-speciﬁc antigen (PSA) •Secretion plays role in sperm activation •1/3 semen volume Bulbo-Urethral Glands (Cowper's Glands) •Pea-sized glands inferior to prostate •Produce thick, clear mucus – Provides lubrication – Neutralizes traces of acidic urine in urethra 3. Describe the components of semen. (Refer to Power Point 27A.) •Mixture of sperm and accessory gland secretions •Secretions enhance chance of sperm survival in male urethra and female reproductive tract •Fructose provides nutrients for ATP synthesis •Alkalinity neutralizes acidity of male urethra and female vagina •Mucus neutralizes acidic urine and provides lubrication •Prostaglandins decrease viscosity of mucus in cervix and stimulate reverse peristalsis in uterus, facilitating sperm movement through female reproductive tract •Antibiotic chemicals destroy bacteria •Clotting factors coagulate semen and cause sperm to stick to vaginal wall •Relaxin hormone enhances sperm motility Gamete Production 4. Compare and contrast mitosis and meiosis. (Refer to Power Point 27B.) •Mitosis – One nuclear division – Two daughter cells – Diploid (2n) – 46 chromosomes – Genetically identical – Growth and repair •Meiosis – Two nuclear divisions – Four daughter cells – Haploid (n) – 23 chromosomes – Genetically distinct – Reproduction and genetic variability 5. Compare and contrast spermatogenesis and oogenesis. What is the function? Where does it occur? When does it begin? How many functional gametes are produced? Is anything else produced? Spermatogenesis : Production of sperm (spermatozoa) in seminiferous tubules of testes – Begins during puberty – Spermatogenic cells give rise to sperm – Spermatogonia (stem cells) divide by mitosis to form two spermatocytes (2n) – Spermatocytes = Type A (germ cells) and Type B – Primary spermatocyte (Type B)  meiosis I – 2 secondary spermatocytes (n)  meiosis II – 4 spermatids (n) – Spermatids become 4 sperm (spermiogenesis) Gametogenesis Most body cells are diploid (2n)  46 chromosomes – Two sets (23 pairs) of chromosomes – Homologous (similar) chromosomes – One set from mother (maternal) – One set from father (paternal) – The two homologues of each chromosome pair carry genes that code for the same traits – Gametes are haploid (n)  23 chromosomes – Contain only one member of homologous pair ***Sperm and egg fuse to form a fertilized egg***  Diploid (46 chromosomes) Spermatogenesis 6. List the stages of sperm development, the types of cell division involved, and the chromosome number of each stage. Mitosis- Spermatogonia form spermatocytes Meiosis- Spermatocytes form spermatids Spermiogenesis- Spermatids become sperm 7. During mitosis of spermatogonia, why don’t both the A and B spermatocytes

BIO | 2111 | Anatomy | study guides | Study Activity - Chapter 27 - 

Rashznique Woods-Gardenhire 8. Discuss the management of sci and the factors that determined the prognosis for this condion. The management and prognosis of SCI is determined by the degree of injury, whether it is complete or incomplete. The ﬁrst year of recovery is the hardest, since the paent is trying to adjust to the condion. Physical and occupaon

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